(y+5)^2=2y^2+5y+31

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Solution for (y+5)^2=2y^2+5y+31 equation:



(y+5)^2=2y^2+5y+31
We move all terms to the left:
(y+5)^2-(2y^2+5y+31)=0
We get rid of parentheses
-2y^2+(y+5)^2-5y-31=0
We add all the numbers together, and all the variables
-2y^2-5y+(y+5)^2-31=0
We move all terms containing y to the left, all other terms to the right
-2y^2-5y+(y+5)^2=31

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